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Informal
5970

Thats basically the same as what I did. But your way is more compact haha

4 Likes
5971

I always simplify steps as much as I can when doing math :joy:

4 Likes
5972

I’ve been doing this kind of maths with my kid recently. so I’m used to writing out each step and explaining it in detail for her lol

4 Likes
5973

On second thought, your way might actually be flawed if the other solution is not 0

3 Likes
5974

I just checked with my wife (Secondary school maths teacher) and she said my method is what they currently teach (so almost certainly not the best method lol)

But either way seems to work. Just don’t ask Copilot for the answer…

Let’s break this down step by step.
The figure consists of two identical rectangles. To find the area of each rectangle, we need to determine the dimensions of one rectangle.
From the given details:

  • The total height of the figure is 20 cm.
  • A smaller section’s width is labeled as 4 cm.

If the two identical rectangles make up the total height, then each rectangle has:

  • A height of ( \frac{20}{2} = 10 ) cm.
  • A width of 8 cm (since the full width isn’t explicitly provided, but reasonable inference suggests it based on standard problems).

Now, calculating the area: [ \text{Area} = \text{Width} \times \text{Height} = 8 \times 10 = 80 \text{ cm}^2 ]
Thus, the correct answer is (3) 80 cm². Let me know if you’d like me to double-check any part!

lol totally wrong

4 Likes
5975

If you need to ask an AI, don’t ask ChatGPT either!

AI ''Summary''

We are given a composite figure made up of two identical rectangles, and we need to find the area of each.

From the image:

  • The total height of the figure is 20 cm.
  • The horizontal part sticking out from the vertical rectangle is 4 cm.
  • Since the figure consists of two identical rectangles, the vertical height of one rectangle must be 10 cm (since 20á2=1020 \div 2 = 1020á2=10).

The small top-right protruding rectangle tells us the width of each rectangle is 4 cm.

So, each rectangle has:

  • Height = 10 cm
  • Width = 4 cm

Area of each rectangle:

Area=height×width=10 cm×4 cm=40 cm2\text{Area} = \text{height} \times \text{width} = 10 , \text{cm} \times 4 , \text{cm} = 40 , \text{cm}^2Area=height×width=10cm×4cm=40cm2

But none of the answer choices list 40 cm². Let’s re-check.

Look again: the entire figure has a total height of 20 cm and the horizontal part sticking out is just the width of one rectangle — 4 cm. But actually, the bottom rectangle’s width is the same as the top one.

So consider this:

  • The width of each rectangle is 8 cm, since the protruding part is half of the full width (assuming the rectangles are stacked to form an “L” shape).

If the full vertical figure is made up of two stacked rectangles, then:

  • Height = 20 cm total ⇒ each rectangle has height = 10 cm
  • Width = 8 cm

So corrected dimensions:

  • Height = 10 cm
  • Width = 8 cm

Area=10×8=80 cm2\text{Area} = 10 \times 8 = 80 , \text{cm}^2Area=10×8=80cm2

Correct answer: (3) 80 cm²

Would you like a labeled diagram to help visualize this?

Also, I agree with @dan3008’s method of math. It’s easier to break it down.

2 Likes
5976

I think Copilot and ChatGPT went to the same maths school lol

4 Likes
5977

The same one that taught them math until 3rd grade? :rofl:

When I told ChatGPT, “Hey, based on 3 calculations (both @Frank419 and @dan3008’s calculations, and my own), answer was 962”. The GPT took 2 paragraphs before it realized that we’re all right and it was wrong!

BTW, if you want Superscript Text, use <sup> and </sup>!

4 Likes
5978

Just to chime in 3 hours after this conversation ended, I like this method better. However, I would argue that your variable should be A (area) instead of S (I think of surface area)

Dan’s method would work a lot better if someone did not fully understand the problem :slight_smile:

5 Likes
5979

I agree with you, Frank’s method is mathmatically better. And what I would use if I was faced with this probem in a real life situation.

I’ve just spent too long helping my daughter with her maths homework so used the method they are teaching her lol

5 Likes
5980

As a person who doesn’t have a full grasp on math (because I thought math was boring (still do), and barely paid any attention in that class), I find that breaking the equation down into simpler terms is sometimes easier. That’s why I agree with @dan3008’s method.

How did it end? I thought conversations ended here when something else is said and we talk about that (like @Oxy’s news).

5 Likes
5981

Quick Note (Thanks @Frank419!)

If you want to show keys, use <kbd> and </kbd>

This is mainly for myself, but knowledge is (a) key!
Knowledge

4 Likes
5982

Not here at China

Both are S for some reason

6 Likes
5983

I solved it thusly:-

Width + length = 20
Average of width and length = 20/2 = 10
Variation from average = 4/2 = 2
Width = 10-2
Length = 10+2

I wonder if AGI will solve most maths problems fastest just by applying trial and error on the basis that this may reach the answer faster than it takes to process the question sufficiently to work out the right way to solve it conventionally..

6 Likes
5984

Thats actually a really clever solution :slight_smile: I like it :slight_smile:

3 Likes
5985

Note the semantic HTML requirements though.

The kbd HTML element is only meant for keyboard keys (thus the name). Using it on all type of buttons is not the best practise.

5 Likes
5986

image
image1366×768 57.2 KB

lol even my blogger site also got ddosed, im so cooked

5987

Ouch! That’s a lot!

1 Like
5988

you… just did someone’s homework…

5989

Copilot uses chaatgpt 4.0 lol